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Автор SHA1 Сообщение Дата
ayan george
738747bd05 build: use $(MAKE) to represent make executable
Prior to this commit, our Makefiles assumed the name of the make program
was simply "make".

Since we use GNU make extensions, this isn't always the case --
operating systems like FreeBSD come with their own implementation named
make which can be incompatible with the extensions used in by tinygo.

To run a compatible make on some of these systems, we have explicitly
call GNU make by running gmake.

This commit changes references to the command "make" to "$(MAKE)" which
is a variable that contains the name of the executable invoked to
process the Makefile.

This allow the Makefiles to be uniformly processed by the same make
program.
2023-10-01 14:55:34 +02:00
Ayke van Laethem
f7f33a1163
docs: add initial documentation 2018-09-23 16:46:57 +02:00