unix: avoid possible heap allocation with -opt=0
This heap allocation would normally be optimized away, but with -opt=0 perhaps not. This is a problem if the conservative GC is used, because the conservative GC needs to be initialized before use.
Этот коммит содержится в:
родитель
dd3d8a363a
коммит
c1aa152a63
1 изменённых файлов: 5 добавлений и 7 удалений
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@ -55,18 +55,16 @@ func main(argc int32, argv *unsafe.Pointer) int {
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cap uintptr
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cap uintptr
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})(unsafe.Pointer(&args))
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})(unsafe.Pointer(&args))
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argsSlice.ptr = malloc(uintptr(argc) * (unsafe.Sizeof(uintptr(0))) * 3)
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argsSlice.ptr = malloc(uintptr(argc) * (unsafe.Sizeof(uintptr(0))) * 3)
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argsSlice.len = 0
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argsSlice.len = uintptr(argc)
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argsSlice.cap = uintptr(argc)
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argsSlice.cap = uintptr(argc)
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// Initialize command line parameters.
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// Initialize command line parameters.
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for *argv != nil {
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for i := 0; i < int(argc); i++ {
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// Convert the C string to a Go string.
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// Convert the C string to a Go string.
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length := strlen(*argv)
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length := strlen(*argv)
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argString := _string{
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arg := (*_string)(unsafe.Pointer(&args[i]))
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length: length,
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arg.length = length
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ptr: (*byte)(*argv),
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arg.ptr = (*byte)(*argv)
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}
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args = append(args, *(*string)(unsafe.Pointer(&argString)))
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// This is the Go equivalent of "argc++" in C.
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// This is the Go equivalent of "argc++" in C.
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argv = (*unsafe.Pointer)(unsafe.Pointer(uintptr(unsafe.Pointer(argv)) + unsafe.Sizeof(argv)))
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argv = (*unsafe.Pointer)(unsafe.Pointer(uintptr(unsafe.Pointer(argv)) + unsafe.Sizeof(argv)))
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}
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}
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